Newton’s second law

لقراءة النسخة العربية أنقر هنا.

Newton’s second law states that the net force on a body and the acceleration it gains are directly proportional. The constant of proportionality is the mass of the object. Mathematical formula of Newton’s second law is:

    \[\sum\overrightarrow{F} = m \bullet \overrightarrow{a}\]

Which is read as “The summation of force vectors on the body is equal to the mass of the body multiplied by its acceleration vector”
In this experiment, the weight of the anvil is supported by the air pressure underneath it, but even though, its huge mass requires huge force to make accelerate (starts from rest to a certain speed).

Similar Posts

  • عزم الدوران

    قد يكون للقوة تأثير دوران (أو تأثير التواء). يعتمد هذا التأثير الدوراني على مقدار القوة  F وعلى مقدار المسافة d من النقطة التي يتم تطبيق القوة عليها بشكل عمودي.

  • Newton’s first law

    In this experiment, the air cushion under the scooter assures that there is almost no friction, so the scooter is acted upon by the gravitational force (its weight) and the reaction of the track. Then we can say that the net force on the scooter is null.
    Now when the scooter is at rest, it remains at rest. But when it is given a push and then is left to move on its own, it will keep moving at constant speed unless it hits the end of the track (a force stops it).

  • Conservation of linear momentum

    If this experiment is done in a situation where the net external force is zero on the loaded cannon just before and just after firing (like when the weight of the cannon is balanced with the normal reaction of the ground), then, when we calculate the product of the mass of the bullet by its velocity and the product of the mass of the cannon by its velocity just before and just after firing, we will find that before firing both were at rest so the product is zero for both, while, after firing, the two products are of the same magnitude but the velocities of the cannon and the bullet are of opposite directions.

  • انحفاظ الزخم الخطي

    لو تم إجراء هذه التجربة في ظروف يكون فيها صافي القوى الخارجية صفرًا على المدفع المُحمّل قبل وبعد إطلاق النار مباشرة (على سبيل المثال، عندما يكون وزن المدفع متوازناً مع رد الفعل العمودي للأرض)، فإن حسبنا عندئذٍ حاصل ضرب كتلة القذيفة بسرعتها المتجهة وحاصل ضرب كتلة المدفع بسرعته المتجهة قبل وبعد الإطلاق مباشرة، سنجد أنه قبل إطلاق النار كان كلاهما في حالة سكون، وبالتالي يكون الناتج صفرًا لكليهما، بينما نجد أن الناتجين، بعد إطلاق النار ذوا مقدار متساوٍ، ولكن باتجاهين متعاكسين.

Leave a Reply

Your email address will not be published. Required fields are marked *

sixteen − 5 =